Question on: JAMB Mathematics - 2009
The probability of a student passing any examination is (\frac{2}{3}). If the student takes three examinations, what is the probability that he will not pass any of them?
A
\(\frac{2}{3}\)
B
\(\frac{4}{9}\)
C
\(\frac{8}{27}\)
D
\(\frac{1}{27}\)
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Correct Option: D
p(pass) = (\frac{2}{3})
p(fail) = (\frac{1}{3})
p(pass at 5 marks) = (\frac{1}{3}) x (\frac{1}{3}) x (\frac{1}{3})
= (\frac{1}{27})
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