Question on: JAMB Mathematics - 2009
The probability of a student passing any examination is \(\frac{2}{3}\). If the student takes three examinations, what is the probability that he will not pass any of them?
A
\(\frac{2}{3}\)
B
\(\frac{4}{9}\)
C
\(\frac{8}{27}\)
D
\(\frac{1}{27}\)
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Correct Option: D
p(pass) = \(\frac{2}{3}\)
p(fail) = \(\frac{1}{3}\)
p(pass at 5 marks) = \(\frac{1}{3}\) x \(\frac{1}{3}\) x \(\frac{1}{3}\)
= \(\frac{1}{27}\)
p(fail) = \(\frac{1}{3}\)
p(pass at 5 marks) = \(\frac{1}{3}\) x \(\frac{1}{3}\) x \(\frac{1}{3}\)
= \(\frac{1}{27}\)
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